How to get an XmlAttribute from an XmlArray?

Question

I have an XML string like this:

<foo>
  ...
  <barlist id="10">
    <bar ... />
    <bar ... />
    etc..
  </barlist>
</foo>

How do I get the id of barlist in deserializing it to an object?

My current code for doing this without serializing/deserializing the ID is this:

class FooData{
  [XmlArray("barlist")]
  [XmlArrayItem("bar",typeof(BarData))]
  public List<BarData> Bars;
}

Can't be done. XML Serialization treats collections as pure collections - it ignores attributes. — John Saunders, May 31 '11 at 15:42
possible duplicate of [XmlSerialize a custom collection with an Attribute](http://stackoverflow.com/questions/377486/xmlserialize-a-custom-collection-with-an-attribute) — John Saunders, May 31 '11 at 15:47

Renatas M. · Answer 1 · 2011-06-01T08:09:50.737

2

Try add XmlAtribute to id object.

UPDATE: I'am adding example how you can deserialize it...

Classes:

[XmlType(AnonymousType=true)]
[XmlRoot(Namespace="", IsNullable=false)]
public class foo {
    [XmlElement("barlist")]
    public List<fooBarlist> barlist { get; set; }
}

[XmlType(AnonymousType=true)]
public class fooBarlist {
    [XmlElement("bar")]
    public List<fooBarlistBar> bar { get; set; }
    [XmlAttribute()]
    public byte id { get; set; }
}

[XmlType(AnonymousType=true)]
public class fooBarlistBar {
    [XmlAttribute()]
    public byte number { get; set; }
    [XmlAttribute()]
    public string value { get; set; }
}

test xml:

<foo>
 <barlist id="1">
  <bar number="1" value="Hi" />
  <bar number="2" value="Hello" />
  </barlist>
  <barlist id="2">
  <bar number="3" value="Bye" />
  <bar number="4" value="Bye bye" />
  </barlist>
</foo>

and the code to deserialize xml to object:

XmlSerializer serializer = new XmlSerializer(typeof(foo));
XmlReader reader = XmlReader.Create("D:\\test.xml");
foo testObj = serialier.Deserialize(reader) as foo;

and then we have result

result

edited Jun 01 '11 at 08:09

answered May 31 '11 at 15:46

Renatas M.

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-1: no, that wouldn't work, even if it were spelled correctly. – John Saunders May 31 '11 at 15:47
@John Saunders: I updated my answer and added test example - it works for me. – Renatas M. May 31 '11 at 16:27
Why do you have `Attribute` at the end of all the names? You know you can leave that off right? – Earlz May 31 '11 at 17:56
so, your point is, if he want to change his classes, then he can do it? – John Saunders May 31 '11 at 18:23
1

I just tryed to show how it can be done thats it. I may be wrong, my answer can be useless to user, but its suggestion. – Renatas M. May 31 '11 at 18:36
This answer worked for me. I hadnt even considered the possibility of not using and XmlArray attribute – tom Oct 04 '21 at 23:59

How to get an XmlAttribute from an XmlArray?

1 Answers1