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I need to help in a small problem , but for me it is big and I haven't found a solution since yesterday

This code works fine for me, but it is displayed to $ watch_server_rows [2] but it does not display to me $ watch_server_rows [1] because writing the code contains an error. I don’t know where it is in

; Or "

Also please do not check in my English and thanks haha 

$newURL =site_url(). "/wp-content/apps/embed.php?v=custom&s=". $watch_server_rows[2];"&set=". $watch_server_rows[1];
user4158643
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  • Is there an error displayed or does something not work? What does `$newURL` contain after this line. – Nigel Ren May 20 '20 at 06:08
  • @NigelRen An error code does not appear, but this code does not work or appears; "& set =". $ watch_server_rows [1]; – user4158643 May 20 '20 at 06:11
  • @user4158643 hello, it's seems that you have a typo with  `;` after ` $watch_server_rows[2]`. If you want to contact string you need to use `.` – GrenierJ May 20 '20 at 06:13

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