I am trying to run through a list of file names, move the file and zip them, then delete the file in gulp. I keep running into the issue that the next task is started before the previous task is finished.
function moveFiles(cb) {
folders.forEach(function(item,index){
var _tmp = '../final_files/' + item;
return Promise.all([
new Promise(function(resolve, reject) {
gulp.src('../' + item + '/**/*').pipe(gulp.dest(_tmp))
.on('end', resolve)
}),
new Promise(function(resolve, reject) {
gulp.src('../master/assets/**/*.*').pipe(gulp.dest(_tmp + '/assets/'))
.on('end', resolve)
}),
new Promise(function(resolve, reject) {
gulp.src([_tmp + '/**', _tmp + '/style/**', _tmp + '/js/**'], {base: "./"})
.pipe(replace('../master/assets', 'assets'))
.pipe(gulp.dest('.'))
.on('end', resolve)
}),
new Promise(function(resolve, reject) {
return gulp.src(_tmp + '/**/*.*')
.pipe(zip(item + '.zip'))
.pipe(gulp.dest( '../final_files/'))
.on('end', resolve)
}),
]).then(function () {
return gulp.src(_tmp, {read: false}).pipe(clean({force: true}));
});
});
}
I've tried to break it out into task, but I can't figure out how to pass a parameter to a task, or have the task wait for it to finish. Any direction would be greatly appreciated.
Regards