python regex: Getting the string in the next line after a given string

Question

I'm working on python script that will extract some words. These words are from a larger text and must be after a given strings and some lines.

Like this: Country --> This is the word I know Judecatoria X/Tribunalul X/Judecatoria Sectorului X --> One of these words are present in the text, however I do not know which of them and I want regex to matched it.

import re

text:"""Country  
     Judecatoria Sectorului X"""

#pattern = this is what I am looking for

expected result:['Judecatoria Sectorului X']

Thank you very much!

You have mentioned twice what your text is. So its hard to know what the text string is ? Is it the one in your code or the one you mention in description above code? — shuberman, May 23 '20 at 08:09

score 0 · Answer 1 · answered May 23 '20 at 08:19

0

Try this,

>>> import re
>>> text = """Country  
...      Judecatoria Sectorului X"""

>>> [x.strip() for x in re.findall("\n.*", text)]
['Judecatoria Sectorului X']

answered May 23 '20 at 08:19

sushanth

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score 0 · Accepted Answer · answered May 23 '20 at 08:19

0

Not sure if I understand the problem correctly, but, if you want to find what is in next line after Country, this should do it:

import re
text = """Country  
     Judecatoria Sectorului X"""
result = re.search('Country\s*\n\s*(.*)\s*', text).group(1)
print(result)

If Country is just an example and it might be one of many words, change Country to (?:Country|Something else|Yet another one)

answered May 23 '20 at 08:19

Błotosmętek

12,717
19
29

Thank you for you answer. For my own edification can you tell me the logic behind the expresion. I would be forever thankful. – Alexandru Manole May 23 '20 at 18:11

python regex: Getting the string in the next line after a given string

2 Answers2