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I need to download a file from a url which has format similar to http://server.com/settings/files/1 when I paste this url in a web-browser this can determine the name of the file to download in this case scheme_563.txt, my question is how I can retrieve the name of the file (which obviously is not included in the url) to download using the wininet functions? currently i am using the HttpQueryInfo function with multiples values like HTTP_QUERY_CONTENT_LOCATION,HTTP_QUERY_CONTENT_DESCRIPTION, etc. but without luck.

mjn
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Salvador
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1 Answers1

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According to http://en.wikipedia.org/wiki/List_of_HTTP_header_fields, the Content-Disposition header includes this information

Content-Disposition: attachment; filename=fname.ext

Maybe this optional header is available in the response to a HTTP GET or HEAD request in this case.

Note that the filename may be encoded - see How to encode the filename parameter of Content-Disposition header in HTTP? for a discussion

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mjn
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