Sorted List Array Question

Question

On sorting an array i get : 1,10,2,3,4,5,6,7,8,9. What went wrong ?

My code was:

        NSArray *sortedArray = [optionKeys sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];

where optionKeys were: 7,3,8,4,9,5,1,6,2,10

i had also tried CaseInsensitiveCompare: and got the same result.

possible duplicate of [How to let the sortedArrayUsingSelector using integer to sort instead of String?](http://stackoverflow.com/questions/2752992/how-to-let-the-sortedarrayusingselector-using-integer-to-sort-instead-of-string) — Seamus Campbell, Jun 01 '11 at 16:01

score 1 · Answer 1 · edited May 23 '17 at 12:18

1

String comparison will place 10 after 1. You'll need to use a number comparison function. This may help: How to let the sortedarrayusingselector using integer to sort instead of string

edited May 23 '17 at 12:18

Community

answered Jun 01 '11 at 16:00

Rob

score 0 · Answer 2 · edited May 23 '17 at 12:34

0

You're doing a string sort rather than a numeric sort. See this answer.

edited May 23 '17 at 12:34

Community

answered Jun 01 '11 at 16:01

Seamus Campbell

score 0 · Answer 3 · edited May 23 '17 at 10:00

0

Check out this answer. You want to do a numeric sort instead of a string sort.

edited May 23 '17 at 10:00

Community

answered Jun 01 '11 at 16:03

DHamrick

3 Answers3