I want to check if a program is running or not, so I searched and I tried this , in this way:
import psutil
if "notepad.exe" in (p.name() for p in psutil.process_iter()):
print('program is running')
else:
print('not running')
but I get this error:
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "~/temp.py", line 2, in <module>
if "notepad.exe" in (p.name() for p in psutil.process_iter()):
File "~/temp.py", line 2, in <genexpr>
if "notepad.exe" in (p.name() for p in psutil.process_iter()):
File "~\Python\Python38-32\lib\site-packages\psutil\__init__.py", line 630, in name
name = self._proc.name()
File "~\Python\Python38-32\lib\site-packages\psutil\_pswindows.py", line 750, in name
return os.path.basename(self.exe())
File "~\Python\Python38-32\lib\site-packages\psutil\_pswindows.py", line 681, in wrapper
raise convert_oserror(err, pid=self.pid, name=self._name)
psutil.AccessDenied: psutil.AccessDenied (pid=6836)
Process finished with exit code 1
am I doing something wrong with this simple code? or is there another alternative way?
EDIT: sorry, i forgot to mention im on windows, not linux, can u give me solutions for windows platform?