How can I remove an object from array in python?

Question

I want to select an msgID and want to delete that full object with username, msg, time_stamp (all of it).

room_msg =  [
 {
  'msgID': 1, 
  'username': 'User1',
  'msg': 'msg1', 
  'time_stamp': 'May-31 05:29PM'},
 {
  'msgID': 2,
  'username': 'User2', 
  'msg': 'msg2', 
  'time_stamp': 'May-31 05:29PM'},
{
  'msgID': 3, 
  'username': 'User3', 
  'msg': 'msg3', 
  'time_stamp': 'May-31 05:29PM'} ]

Like if I select 'msgID': 3 after deleting the 'msgID': 3 the array should like this

room_msg = [
 {
  'msgID': 1, 
  'username': 'User1',
  'msg': 'msg1', 
  'time_stamp': 'May-31 05:29PM'},
 {
  'msgID': 2,
  'username': 'User2', 
  'msg': 'msg2', 
  'time_stamp': 'May-31 05:29PM'}
]

Is that possible? I can't find x with that msgID room_msg[x].

FWIW: Python has lists as the basic sequence collection type, not arrays; [..] creates a list. There are many examples on how to manipulate lists - now using the right terminology, try some internet/SO searches. “python remove list item by property” (eg.) — user2864740, May 31 '20 at 21:51
Does this answer your question? [Is there a simple way to delete a list element by value?](https://stackoverflow.com/questions/2793324/is-there-a-simple-way-to-delete-a-list-element-by-value) — sahasrara62, May 31 '20 at 22:07

score 1 · Answer 1 · answered May 31 '20 at 21:50

You can use list comprehension:

room_msg = [m for m in room_msg if m['msgID'] != 3]

from pprint import pprint
pprint(room_msg)

Prints:

[{'msg': 'msg1',
  'msgID': 1,
  'time_stamp': 'May-31 05:29PM',
  'username': 'User1'},
 {'msg': 'msg2',
  'msgID': 2,
  'time_stamp': 'May-31 05:29PM',
  'username': 'User2'}]

score 1 · Accepted Answer · answered May 31 '20 at 21:52

1

This simple code should do it:

desired_id = 3  # example id

for i, msg in enumerate(room_msg):
    if msg['msgID'] == desired_id:
        del room_msg[i]

answered May 31 '20 at 21:52

snatchysquid

1,283
9
24

score 0 · Answer 3 · answered May 31 '20 at 21:50

0

Try using del on the matching array indices.

for index, msg in enumerate(room_msg):
    if msg['msgID'] == 3:
        del room_msg[index]

answered May 31 '20 at 21:50

Heitor Chang

6,038
2
45
65

score 0 · Answer 4 · answered May 31 '20 at 21:54

This could be a way - or you use the msgID as Ident for nested - than you can erase with del room_msg[msg]

def search_and_delete(msg):
    count = 0
    for x in room_msg:
        if x['msgID'] == msg:
            room_msg.pop(count)
        count+=1

score 0 · Answer 5 · answered May 31 '20 at 22:22

0

To delete a object from an array in python use

del arr["index"]

answered May 31 '20 at 22:22

Damnik Jain

374
2
11

How can I remove an object from array in python?

5 Answers5