Python Iterate Through a Dictionary

Question

I have dictionary like below

x_wins = {'row1_X': 'X' == x_o[0] and 'X' == x_o[1] and 'X' == x_o[2],
'row2_X' : 'X' == x_o[3] and 'X' == x_o[4] and 'X' == x_o[5],
'row3_X' : 'X' == x_o[6] and 'X' == x_o[7] and 'X' == x_o[8],
'col1_X' : 'X' == x_o[0] and 'X' == x_o[3] and 'X' == x_o[6],
'col2_X' : 'X' == x_o[1] and 'X' == x_o[4] and 'X' == x_o[7],
'col3_X' : 'X' == x_o[2] and 'X' == x_o[5] and 'X' == x_o[8],
'slant1_X' : 'X' == x_o[0] and 'X' == x_o[4] and 'X' == x_o[8],
'slant2_X' : 'X' == x_o[2] and 'X' == x_o[4] and 'X' == x_o[6]
}

and I want to check if any key gives True. How can I do it? Thx for help.

`any(x_wins.values())` – Dillon Miller Jun 02 '20 at 19:27 — Dillon Miller, Jun 02 '20 at 19:27

geoph9 · Answer 1 · 2020-06-02T19:28:26.380

1

You can check if any of the dictionary values are true:

if True in x_wins.values():
  print("Success!")
else:
  print("All False...")

You could also use any like this: if any(x_wins.values()): ...

If you want to get the key for which the value is True then:

valid_keys = [key for key, val in x_wins.items() if val is True]

This will give the list of all keys that have a value of True.

edited Jun 02 '20 at 19:28

answered Jun 02 '20 at 19:25

geoph9

357
3
18

But then how could you know which `key` is the successful one? – Celius Stingher Jun 02 '20 at 19:26
1

see my edit @CeliusStingher – geoph9 Jun 02 '20 at 19:28
Thanks! It;s rly simple and right idea : ) – Joe Jun 02 '20 at 19:58

score 1 · Answer 2 · answered Jun 02 '20 at 19:26

You can use a list comprehension to find the "True" keys if I understand correctly:

true_keys = [x for x in x_wins if x_wins[x] == True]

Example:

x_o =['X','X','X',0,0,0,'X','X','X']
x_wins = {'row1_X': 'X' == x_o[0] and 'X' == x_o[1] and 'X' == x_o[2],
'row2_X' : 'X' == x_o[3] and 'X' == x_o[4] and 'X' == x_o[5],
'row3_X' : 'X' == x_o[6] and 'X' == x_o[7] and 'X' == x_o[8],
'col1_X' : 'X' == x_o[0] and 'X' == x_o[3] and 'X' == x_o[6],
'col2_X' : 'X' == x_o[1] and 'X' == x_o[4] and 'X' == x_o[7],
'col3_X' : 'X' == x_o[2] and 'X' == x_o[5] and 'X' == x_o[8],
'slant1_X' : 'X' == x_o[0] and 'X' == x_o[4] and 'X' == x_o[8],
'slant2_X' : 'X' == x_o[2] and 'X' == x_o[4] and 'X' == x_o[6]
}
true_keys = [x for x in x_wins if x_wins[x] == True]
print(true_keys)

Output:

['row1_X', 'row3_X']

score 0 · Answer 3 · answered Jun 02 '20 at 19:27

0

You can do that with the any function.

The following will print win if any values of the x_wins dict is True :

if any(x_wins.values()):
    print('win!')

answered Jun 02 '20 at 19:27

A-y

793
5
16

Python Iterate Through a Dictionary

3 Answers3