Access ForeignKey set directly in template in Django

Question

I have this simplified model:

class Item(models.Model):
    name = models.CharField(max_length=120)

class ItemImage(models.Model):
    image = models.ImageField(upload_to='upload_dir')
    item = models.ForeignKey(Item)

An Item can have many ItemImages. I also have a template rendering the following data set from the view:

items = Item.objects.all()

So now I would want to do something like this in the template:

{% for item in items %}
<div>
    {{ item.name }}<br>
    <img src="{{ item.itemimage_set.all()[0] }}">
</div>
{% endfor %}

But obviously that's not possible. Not from the template directly, at least.

What is the proper way to get the equivalent of the first image inside the template?

Andrey Fedoseev · Accepted Answer · 2011-06-02T19:20:06.723

74

{% with item.itemimage_set.all|first as image %}
  <img src="{{ image.url }}" />
{% endwith %}

edited Jun 02 '11 at 19:20

answered Jun 02 '11 at 17:29

Andrey Fedoseev

5,222
1
24
19

1

this is really a nice solution. i always forget about the with tag. – arie Jun 02 '11 at 20:35
As of django 2.2 a neater way to write it can be `{% with image=item.itemimage_set.all|first %}` . Reference [here](https://docs.djangoproject.com/en/2.2/ref/templates/builtins/#with). – Josh Apr 16 '20 at 15:35
It should be – nilansh bansal Jun 10 '20 at 15:48

arie · Answer 2 · 2011-06-02T17:43:27.557

Or you could add a method to your Item model:

def get_first_image(self):
    return self.itemimage_set.all()[0]

and then call this method in your template:

{{ item.get_first_image }}

Or you could use:

{{ item.itemimage_set.all.0 }}

and to get the first image's url:

<img src="{{ item.itemimage_set.all.0.url }}">

Though if you need more flexibility (more than one picture in certain cases, etc.) it's probably best to write a little templatetag.

score 9 · Answer 3 · answered Jun 02 '11 at 17:04

9

One possible way would be to iterate over all the ItemImages like so:

{% for item in items %}
<div>
    {{ item.name }}<br>
    {% for image in item.itemimage_set.all %}
    <img src="{{ image.image.url }}">
    {% endfor %}
</div>
{% endfor %}

answered Jun 02 '11 at 17:04

Yuval Adam

161,610
92
305
395

Brian Sanchez · Answer 4 · 2023-02-10T16:01:12.080

4

This worked for me, use the related_name in your models.

models.py

class Building(models.Model):
    address  = models.CharField(max_length=200, blank=True, null=True)
    city     = models.CharField(max_length=200, blank=True, null=True)

class Space(models.Model):
    title     = models.CharField(max_length=200, blank=True, null=True)
    building  = models.ForeignKey(Building, related_name="spaces_of_this_building")

buildings.html

{% for space in building.spaces_of_this_building.all %}
  {{ space.title }}
{% endfor %}

edited Feb 10 '23 at 16:01

answered Sep 05 '13 at 00:36

Brian Sanchez

832
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13
11

am I missing something: where is size defined? Is this built in, or is this another attribute of the Building model? Thanks. – BLimitless Feb 09 '23 at 05:02

score 2 · Answer 5 · answered Jan 10 '12 at 09:42

2

If you want the first picture from set you can do:

{% for item in item.image_set.all %}

{{if forloop.first }}
<img src="{{ item.url }}">
{% endif %}

{% endfor %}

But i also love Andray solution with 'with'

answered Jan 10 '12 at 09:42

zzart

11,207
5
52
47

This isn't a very elegant solution. `{% with %}` absolutely solves it. – Yuval Adam Jan 10 '12 at 11:10

Access ForeignKey set directly in template in Django

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