How can I use a single command to unzip every file in a directory, into a new unique directory with the same name as the file

Question

I have a directory full of zip files. Each called something like 'files1.zip'. My instinct is to use a bash for loop to unzip each file.

Trouble is, many of the files will unzip their contents straight into the parent directory, rather then unfolding everything into their own unique directory. So, I get file soup.

I'd like to ensure that 'files1.zip' pours all of it's files into a dir called 'files1', and so on.

As an added complication, some of the filenames have spaces.

How can I do this?

Thanks.

Related: [http://stackoverflow.com/q/2463874/435605](http://stackoverflow.com/q/2463874/435605) — AlikElzin-kilaka, Jul 14 '16 at 07:03

score 19 · Accepted Answer · answered Jun 02 '11 at 20:50

19

for f in *.zip; do
  dir=${f%.zip}

  unzip -d "./$dir" "./$f"
done

answered Jun 02 '11 at 20:50

Roland Illig

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score 0 · Answer 2 · edited Jan 31 '17 at 15:50

0

Simple one liner

$ for file in `ls *.zip`; do unzip $file -d `echo $file | cut -d . -f 1`; done

edited Jan 31 '17 at 15:50

Konrad

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answered Nov 09 '16 at 21:01

SJK

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Your code doesn't work for zip file names having spaces or starting with a hyphen. – Roland Illig Jun 14 '18 at 18:39

score -1 · Answer 3 · answered Jun 02 '11 at 20:46

-1

you can use -d to unzip to a different directory.

for file in `echo *.zip`; do
    [[ $file =~ ^(.*)\.zip$ ]]
    unzip -d ${BASH_REMATCH[1]} $file
done

answered Jun 02 '11 at 20:46

Kim Stebel

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`echo *.zip` won't work for zip file names that contain spaces. – Neil Jun 02 '11 at 20:48

How can I use a single command to unzip every file in a directory, into a new unique directory with the same name as the file

3 Answers3