grep string with special characters in file

Question

my file contains:

/*uid:68160*/\n            SELECT
/*uid:68160*/SELECT

I tried with below:

grep -vF "/[*]uid::[[:digit:]][*]/SELECT"

which is helping to removed 2nd line. How to remove 1st line by grep also tried:

grep -vF "/[*]uid::[[:digit:]][*]/\n            SELECT"

Please see [How do I format my code blocks?](//meta.stackexchange.com/q/22186) — oguz ismail, Jun 05 '20 at 05:05
Multiline regexp: https://stackoverflow.com/questions/3717772/regex-grep-for-multi-line-search-needed — Nigredon, Jun 05 '20 at 05:11
@AbhijitShinde : Why did you use `-F`? This option means (from the man-page) _Interpret PATTERN as a list of **fixed** strings (instead of regular expressions)_ — user1934428, Jun 05 '20 at 07:00

score 1 · Answer 1 · answered Jun 05 '20 at 08:01

Assuming you have a literal text like that,

s='/*uid:68160*/\n            SELECT
/*uid:68160*/SELECT
Text'

and you want to remove lines 1 and 2, you may use

 grep -Ev '/[*]uid:[[:digit:]]+[*]/(\\n *)?SELECT'

Details

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