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The answer should be 163271004971660485, but it gives 163271004971660480 as the answer. Using int(326542009943320970/2) gives the same incorrect result.

Dycey
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noob
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  • Did you try `round(326542009943320970//2)` ? – Austin Jun 05 '20 at 08:35
  • I'm not so versed in Python, but I found this link to be useful: https://realpython.com/python-rounding/ – Paul Jun 05 '20 at 08:37
  • See also [Python and “arbitrary precision integers”](https://stackoverflow.com/questions/21031093/python-and-arbitrary-precision-integers) – Pac0 Jun 05 '20 at 08:38
  • Short version of the duplicate: your number is too large to represent as a float, and `/` is floating-point division. You need to start with integer division `//` – `326542009943320970 // 2` is the correct, precise version of the incorrect `int(326542009943320970 / 2)` – then apply rounding manually by adding 1 based on whether the input is even or odd with the help of the `%` operator. – Ry- Jun 05 '20 at 08:39
  • @Austin no need for`round`, but `//` is indeed important here – Pac0 Jun 05 '20 at 08:39
  • @Austin Thanks, that works. Do you know what causes this problem? – noob Jun 05 '20 at 08:39
  • @noob seems Ry was writing the explanation while you were writing your comment :) – Pac0 Jun 05 '20 at 08:40
  • Please see the linked duplicate. – Austin Jun 05 '20 at 08:41

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