Here is my ng-pattern= "/^[0-9]+(.[0-9][0-9])?$/i" which will allow only any digits and decimal followed by 2 digits, but I want it to match empty string too.
How can I do it?
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Wiktor Stribiżew
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Deeksha
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Use `^(?:pattern)?$`. Note you need to escape `.` to match a literal `.` – Wiktor Stribiżew Jun 05 '20 at 13:45
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A quick change you could make to that regex is swap + for * `"/^[0-9]*(.[0-9][0-9])?$/i"` – Rob Streeting Jun 05 '20 at 13:47