How to convert a string which contains a hexadecimal number to an int in c

Asked Jun 05 '20 at 14:12

Active Jun 05 '20 at 14:14

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I have a situation where I have a char *, called number, which will either contain a decimal number in the form of ("123") or a hexadecimal number in the form ("0x123"), where 123 is arbitrary;

What is the best way to convert this string to an integer considering I don't know which format the char * will be in?

edited Jun 05 '20 at 14:14

NathanOliver

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asked Jun 05 '20 at 14:12

dilan_s

You must search the string for `0x`. If found, convert to `int` using `strtol`, for example, with base of `16` or `10`. – Fiddling Bits Jun 05 '20 at 14:15
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@FiddlingBits Just use `strtol()` with a base of `0`. If the data is decimal but can still start with 0, use a base `10` so the string is treated as decimal instead of octal. – Andrew Henle Jun 05 '20 at 14:16
@AndrewHenle Even better. – Fiddling Bits Jun 05 '20 at 14:18

How to convert a string which contains a hexadecimal number to an int in c

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