Why variable inside function is being used outside the JavaScript function?

Asked Jun 06 '20 at 00:27

Active Jun 06 '20 at 00:35

Viewed 28 times

I am new and learning JavaScript from Udemy

What answer should be according to Udemy Course

Question is age variable is declared globally so the second console.log should be 23 which is outside the function what am i doing wrong ? but the console.log is taking the variable from the function !

edited Jun 06 '20 at 00:35

asked Jun 06 '20 at 00:27

Mitul Pancholi

thats the way javascript works. – Daniel A. White Jun 06 '20 at 00:30
3

Please paste code in the question and use the formatting tools. Don't post images of code. – Mark Jun 06 '20 at 00:30
@DanielA.White As per Udemy Course it should be 23 so is that guy teaching me wrong ! – Mitul Pancholi Jun 06 '20 at 00:34
1

`age = 65` changes the variable declared `var age = 23` which is in global scope. Try `var age = 65` inside of `foo` for a different result. Or try putting `var age = 23` *after* your definition of `foo`. – lurker Jun 06 '20 at 00:34
You will find a very complete answer here: https://stackoverflow.com/a/500459/1978785 – Charlie Wallace Jun 06 '20 at 00:35
blocks in javascript doesn't define a new scope. that's why this is happening. – Sahil Jun 06 '20 at 00:39
Thank You all ! Found the solution for my problem in udemy they declared a variable inside function " var age = 65 " which didnt changed variable var age = 23 . which i didnt do it in my code ! – Mitul Pancholi Jun 06 '20 at 00:49
Yep, the details matter. :) – lurker Jun 06 '20 at 02:08

Why variable inside function is being used outside the JavaScript function?

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