I have a list as follows:
sample = ['a', 'b', 'c', None]
My Code is :
sample_out = ','.join(sample)
Error:
TypeError: sequence item 3: expected string, NoneType found
Could someone point me out how to handle the None?
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Tomerikoo
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Arun Sunderraj
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Does this answer your question? [Join a list of items with different types as string in Python](https://stackoverflow.com/questions/3590165/join-a-list-of-items-with-different-types-as-string-in-python) – Tomerikoo Jun 06 '20 at 13:27
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You didn't specify how you actually **want** to *handle* the `None`... Do you want to add it to the string? Filter it out? print a warning? – Tomerikoo Jun 06 '20 at 13:31
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if you could provide the expected output that would make things easier – Anurag Wagh Jun 06 '20 at 13:32
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I would filter out the None and result would be like a,b,c – Arun Sunderraj Jun 06 '20 at 13:33
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In that case, here is the correct dup: https://stackoverflow.com/questions/14229433/native-python-function-to-remove-nonetype-elements-from-list – Tomerikoo Jun 06 '20 at 13:38
