Initialize a number of instances inside a list

Asked Jun 10 '20 at 08:52

Active Jun 10 '20 at 08:52

Viewed 42 times

any more efficient or shorter way to initialize a number of instance inside a List<>

List<SomeObject> contrats = new List<SomeObject>();
for (int i = 1; i <= rowCount; i++) 
     contrats.Add(new SomeObject());

asked Jun 10 '20 at 08:52

David Benichou

5

You can do things like `Enumerable.Range(0, rowCount).Select(x => new SomeObject()).ToList()`, but it's not that much neater. One small improvement to your current approach would be `new List(rowCount)` – canton7 Jun 10 '20 at 08:53
1

Your current approach is pretty fine already – Pavel Anikhouski Jun 10 '20 at 08:55

0 Answers0