How can I translate this Lambda expression into a Python 'def' function?

Question

How can I translate the following lambda expression into normal Python functions? What mistakes did I make, and what are the best ways to approach them?

love = lambda x: lambda y: lambda z: x + y * z

def love(x):
    def love(y):
        def love(z):
            return x + y * z
        return love
print(love(x))
print(love(y))
print(love(z))

Relates to [Understanding nested lambda function behaviour in python](https://stackoverflow.com/questions/36391807/understanding-nested-lambda-function-behaviour-in-python) — DarrylG, Jun 14 '20 at 13:41

score 2 · Accepted Answer · answered Jun 14 '20 at 13:40

2

It should return function for first two arguments.

def love(x):
    def f1(y):
        def f2(z):
            return x+y*z
        return f2
    return f1

print(love(2)(3)(4))  # return 2+3*4
# 14

answered Jun 14 '20 at 13:40

Jason Yang

11,284
2
9
23

Oh, I like this one! – George Udosen Jun 14 '20 at 13:44
here is the answer I'm looking for, thank you very much – Jun 14 '20 at 13:48

score 1 · Answer 2 · answered Jun 14 '20 at 13:30

1

lamda x, y, z : x + y * z

therefore:

def func(x, y, z):
    return x + y * z

answered Jun 14 '20 at 13:30

jupiterbjy

2,882
1
10
28

1

I would have thought so too! – George Udosen Jun 14 '20 at 13:33
Post is a nested lambda expression [Understanding nested lambda function behaviour in python](https://stackoverflow.com/questions/36391807/understanding-nested-lambda-function-behaviour-in-python) so returns a function not a number. – DarrylG Jun 14 '20 at 13:45
Well, I thought he didn't know about lambda taking multiple inputs. – jupiterbjy Jun 14 '20 at 13:52

How can I translate this Lambda expression into a Python 'def' function?

2 Answers2