is there any way to let this code know g is defined?

Question

please help, I cant find out why this is throwing the error. I've tried everything I can think of, why is this.runLoop() defined and suddenly this.processInput() not, I'm trying to understand classes better and I finally thought I got it, I guess not

    
class Game {
    constructor(teamSize){
        this.cpu1 = new Array(teamSize-1);
        this.cpu2  = new Array(teamSize);
        this.run = -1;
        this.init();  
    }

    init(){
    }


    shutdown(){};

    processInput = function(elapsed) {
      console.log(elapsed);
    }
    updateGame(elapsed){}
    generateOutput(elapsed){
    }

    runLoop(timestamp){
        let last;
        if(last === undefined){
            last = timestamp;
        }
        let elapsed = timestamp - last;

        this.processInput(elapsed);
        this.updateGame(elapsed);
        this.generateOutput(elapsed);
        
        last = timestamp;
        if(this.run == 1){
        window.requestAnimationFrame(this.runLoop);
        }
    };

  start(){
        this.run *= -1;
        if(this.run == 1){
        window.requestAnimationFrame(this.runLoop);
        }
    }
   
};

var g = new Game(5);
g.start();

does the error have something to do with the window.requestAnimationFrame() does that become the object 'this' would be referring to?

Thanks for including the live snippet, but unfortunately, your title mentions one error, but the snippet throws a different error. Please state clearly what code is throwing the error and what error is being thrown (copy and paste the error). (Re the title: `g` is definitely defined.) — T.J. Crowder, Jun 14 '20 at 17:40
The error the snippet throws is explained [here](http://stackoverflow.com/questions/20279484/how-to-access-the-correct-this-context-inside-a-callback), if that's what you're running into. — T.J. Crowder, Jun 14 '20 at 17:42
@T.J.Crowder — They seem to match up to me. "Uncaught TypeError: Cannot read property 'processInput' of undefined" and `this` is expected to be `g` but is `undefined`. The question could be clearer though. — Quentin, Jun 14 '20 at 17:42

is there any way to let this code know g is defined?

0 Answers0