What is the recipient's length in email in python 3?

Question

I wrote a script in python 3 to send a notification mail to list of stakeholders. I have observed that the last address in the mail received gets trimmed off the moment I give more than 255 characters in the "To" field.

Sample Code:

#me == the sender's email address
me = "myemail@email.com"
#you == the recipient's email address
you = "a1@email.com;a2@email.com;..."
msg['To'] = you
msg = MIMEMultipart('alternative')
msg['Subject'] = "Test mail"
msg['From'] = me
msg['To'] = you

part1 = MIMEText(text, 'plain')
part2 = MIMEText(messages, 'html')

msg.attach(part1)
msg.attach(part2)

s = smtplib.SMTP('localhost')
s.sendmail(me, you, msg.as_string())

For example, in the you field, person1@email.com, if s is the 255th character, then in the output mail, recipients field will be till pers from the left, rest gets trimmed off. How to overcome these?

Also, few questions:

Please provide the RFC or documentation on these. I checked in rfc822. Not much info present.
Is this related to Mime or smtplib module?

https://stackoverflow.com/questions/8856117/how-to-send-email-to-multiple-recipients-using-python-smtplib might help. — apoorva kamath, Jun 15 '20 at 10:28
Thanks, for the links, if I use recipients as list and then use the join to make the recipient string, it works. But I want to understand why? — Dr. Essen, Jun 15 '20 at 11:42
Sorry, it didn't work. It worked for mail recipient string length <= 255. — Dr. Essen, Jun 15 '20 at 12:14

score 0 · Answer 1 · answered May 31 '22 at 05:38

Yes, using recipients as list and then using the join to make the recipient string works even for characters>=255.

(Use "," instead of "';" as separater)

Syntax that worked for me:

you = ["abc@gmail.com", "bcd@gmail.com", ...]
msg["to"] = ",".join(you)
s.send_message(msg)

What is the recipient's length in email in python 3?

1 Answers1