In a ListView, how can I open different URLs depending on which list item I have tapped on?

Question

I am using ListView from Xamarin.Forms for my project. I have a List<MyObject>, where each object MyObject has an individual URL property. The List is used as the ItemsSource for the ListView. How can I let each list item open the URL it has been assigned to, when clicked on?

Have you tried using reflexion on your list? Or maybe a simple foreach-loop? — Adrian Efford, Jun 15 '20 at 10:07
@AdrianEfford What do you mean with reflexion? I didn't find anything about it on google. — taratect, Jun 15 '20 at 10:17
Reflection sorry... Here a link: https://stackoverflow.com/questions/15234236/reflection-on-list-and-printing-values — Adrian Efford, Jun 15 '20 at 10:19
You are looking for OnClickEvent for list item, here is how you do it https://www.codemahal.com/video/adding-click-events-to-a-listview-in-android-with-xamarin/ — Ali, Jun 15 '20 at 10:28
See the answer from Jason, but native is really easy to convert to Forms :) — Ali, Jun 16 '20 at 02:37

score 0 · Accepted Answer · answered Jun 15 '20 at 12:23

0

use the ItemSelected event

protected void ListView_ItemSelected(object sender, SelectedItemChangedEventArgs args)
{
  var item = (MyObject)args.SelectedItem;
  var url = item.Url;

  Device.OpenUri(url);
}

answered Jun 15 '20 at 12:23

Jason

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In a ListView, how can I open different URLs depending on which list item I have tapped on?

1 Answers1