Trying to remove with if in python but not working?

Asked Jun 15 '20 at 19:01

Active Jun 15 '20 at 19:08

Viewed 43 times

I have used the below code to remove 20 from list1

list1 = [5, 20, 15, 20, 25, 50, 20]
if 20 in list1:
    list1.remove(20)

It doesn't remove instead if i do it this way first:

list1.remove(20)

but the above line only removes the first occurrence of it but when i run the if loop again, it removes the last occurrence too.

Why if loop doesn't work without that?

list1 = [5, 20, 15, 20, 25, 50, 20]
a = 20
if a in list1:
    list1.remove(a)

>>> print(list1)
[5, 15, 20, 25, 50, 20]

edited Jun 15 '20 at 19:08

wjandrea

asked Jun 15 '20 at 19:01

Natan

2

`.remove()` always removes the _first occurrence_ of whatever its argument is. Can you post the _full code_ that's giving you an error, and not just the one line? – Green Cloak Guy Jun 15 '20 at 19:04
Try the code from here https://www.includehelp.com/python/remove-all-occurrences-a-given-element-from-the-list.aspx – Yonah Dissen Jun 15 '20 at 19:05
1

Please show the exact code and effects. What loop? – Mad Physicist Jun 15 '20 at 19:05
Just replace your `if` with `while` to make it remove all occurences of `20` – Mandera Jun 15 '20 at 19:06
thanks. while loop solves but i wonder IF fails to do it. still stuck with MS excel. – Natan Jun 15 '20 at 19:08
`if` is not a loop. I think you meant `while` in the first place. – wjandrea Jun 15 '20 at 19:09

0 Answers0