Create intervals of size N from a given integer

Question

Lets say I have an integer for example 6350 . How can I create intervals of size N (lets say 500) that results in the following ranges:

[0, 500, 1000, 1500, 2000 ... 6000, 6350]

Does this answer your question? [Java: how can I split an ArrayList in multiple small ArrayLists?](https://stackoverflow.com/questions/2895342/java-how-can-i-split-an-arraylist-in-multiple-small-arraylists) — azro, Jun 15 '20 at 21:00

Mark Bramnik · Accepted Answer · 2020-06-15T21:24:10.307

2

The most obvious java only (no third parties) solution:

int max = 6350;
int N = 500;

List<Integer> result = new ArrayList<>();

for(int i = 0 ; i < max; i+=N) {
    result.add(i);
}

result.add(max);

The result array list should look like exactly as you’ve posted in the question

edited Jun 15 '20 at 21:24

answered Jun 15 '20 at 21:07

Mark Bramnik

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6500 is part of the result – azro Jun 15 '20 at 21:13
Because Mark wrote `int max = 6530;` instead of `int max = 6350;` – Jesper Jun 15 '20 at 21:23
Sorry, it was a typo, fixed – Mark Bramnik Jun 15 '20 at 21:24
I like what you did at the end, add max :) – fareed Jun 16 '20 at 23:18

score 1 · Answer 2 · answered Jun 15 '20 at 21:39

1

You can use IntStream

    int limit = 6350;
    int interval = 500;
    int[] array = IntStream.iterate(0, i -> i < limit, i -> i + interval).toArray();

answered Jun 15 '20 at 21:39

0xh3xa

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score 1 · Answer 3 · answered Jun 15 '20 at 21:52

Using streams as a replacement of for loop:

final int MAX = 6350, INC = 500;
Stream.concat(
    Stream.iterate(0, i -> i < MAX, i -> i + INC),
    Stream.of(MAX)
)
.collect(Collectors.toList()) // may be skipped
.forEach(System.out::println);

prints sequence:

Create intervals of size N from a given integer

3 Answers3