Python get info from long complicated string

Question

Im trying to get info from strings that I have parsed. Im trying to get the font size. This is the string Im returning

style="fill: rgb(0, 0, 0); fill-opacity: 1; font-family: ProjectStocksFont; font-size: 70px; font-weight: normal; font-style: normal; text-decoration: none;"

Im trying to get 70 from font-size what would the best way to do that be?

score 1 · Accepted Answer · answered Jun 20 '20 at 23:06

1

You can use re module for the task:

style="fill: rgb(0, 0, 0); fill-opacity: 1; font-family: ProjectStocksFont; font-size: 70px; font-weight: normal; font-style: normal; text-decoration: none;"

import re

print( re.search(r'font-size:\s*(\d+)', style)[1] )

Prints:

answered Jun 20 '20 at 23:06

Andrej Kesely

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What if I was trying to get the ```rgb``` values? I was hoping to put it into a list so I could use the rgb values some where like ```rgb[0], rgb[1], rgb[2]``` – Jack Soder Jun 25 '20 at 01:54
@JackSoder Do you want to get the RGB values of `fill: rgb(0, 0, 0);`? – Andrej Kesely Jun 25 '20 at 07:42
Yeah thats what im trying to get – Jack Soder Jun 25 '20 at 22:55

score 1 · Answer 2 · answered Jun 20 '20 at 23:10

Alternatively, you can parse the string to a dictionary. This might be useful if you want to access more than just that property.

style_dict = dict([[a.strip() for a in s.split(':')] for s in style.split(';') if s != ""])
style_dict['font-size']

Gives

'70px'

If you don't want the units:

style_dict['font-size'][:-2]

Cole Draper · Answer 3 · 2020-06-20T23:25:54.543

1

You can use regular expressions to find what you need

    import re

    style="fill: rgb(0, 0, 0); fill-opacity: 1; font-family: ProjectStocksFont; font- 
    size: 70px; font-weight: normal; font-style: normal; text-decoration: none;"

    fontSize = re.findall("font-size: (.+)px",style)[0] # returns '70'

https://www.w3schools.com/python/python_regex.asp

edited Jun 20 '20 at 23:25

answered Jun 20 '20 at 23:15

Cole Draper

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3

While the OP's question uses px as units, there are other valid units for font-size in CSS. This will fail in those other cases. – Michael Ruth Jun 20 '20 at 23:25

score 1 · Answer 4 · answered Jun 20 '20 at 23:18

Using the .split() method is one approach.

You can split the string into a python list to separate each kind of entry in your string. Then you can iterate though your list splitting each sub-string and save your values in a python dictionary.

style = "fill: rgb(0, 0, 0); fill-opacity: 1; font-family: ProjectStocksFont; font-size: 70px; font-weight: normal; font-style: normal; text-decoration: none;"
style_dict = {}
style = style.split("; ")

for item in style:
    key, value = item.split(": ")
    style_dict[key] = value

key = "font-size"
print(style_dict[key])

score 0 · Answer 5 · answered Jun 20 '20 at 23:06

You can use a regex to accomplish this, but it would be better to use some package that understands CSS. Anyways, give this a try:

import re


style="fill: rgb(0, 0, 0); fill-opacity: 1; font-family: ProjectStocksFont; font-size: 70px; font-weight: normal; font-style: normal; text-decoration: none;"
font_size = re.match(r'.*font-size: ([^;^a-z]+).*', style)

Python get info from long complicated string

5 Answers5

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