I have a date as a string in the following format "04/02/2011 20:27:05". I am using Joda-Time library and would like to convert it to DateTime object. I did:
DateTime dt = new DateTime("04/02/2011 20:27:05")
But I'm getting the following error :
Invalid format: "04/02/2011 14:42:17" is malformed at "/02/2011 14:42:17"
How to convert the above date to a DateTime object?
Use DateTimeFormat:
DateTimeFormatter formatter = DateTimeFormat.forPattern("dd/MM/yyyy HH:mm:ss");
DateTime dt = formatter.parseDateTime(string);
I know this is an old question, but I wanted to add that, as of JodaTime 2.0, you can do this with a one-liner:
DateTime date = DateTime.parse("04/02/2011 20:27:05",
DateTimeFormat.forPattern("dd/MM/yyyy HH:mm:ss"));
DateTimeFormat.forPattern("dd/MM/yyyy HH:mm:ss").parseDateTime("04/02/2011 20:27:05");
From comments I picked an answer like and also adding TimeZone:
String dateTime = "2015-07-18T13:32:56.971-0400";
DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss.SSSZZ")
.withLocale(Locale.ROOT)
.withChronology(ISOChronology.getInstanceUTC());
DateTime dt = formatter.parseDateTime(dateTime);
Your format is not the expected ISO format, you should try
DateTimeFormatter format = DateTimeFormat.forPattern("dd/MM/yyyy HH:mm:ss");
DateTime time = format.parseDateTime("04/02/2011 20:27:05");
You can also use SimpleDateFormat, as in DateTimeFormat
Date startDate = null;
Date endDate = null;
try {
if (validDateStart!= null) startDate = new SimpleDateFormat("MM/dd/yyyy HH:mm", Locale.ENGLISH).parse(validDateStart + " " + validDateStartTime);
if (validDateEnd!= null) endDate = new SimpleDateFormat("MM/dd/yyyy HH:mm", Locale.ENGLISH).parse(validDateEnd + " " + validDateEndTime);
} catch (ParseException e) {
e.printStackTrace();
}
java.time.LocalDateTime.parse(
"04/02/2011 20:27:05" ,
DateTimeFormatter.ofPattern( "dd/MM/uuuu HH:mm:ss" )
)
The modern approach uses the java.time classes that supplant the venerable Joda-Time project.
Parse as a LocalDateTime as your input lacks any indicator of time zone or offset-from-UTC.
String input = "04/02/2011 20:27:05" ;
DateTimeFormatter f = DateTimeFormatter.ofPattern( "dd/MM/uuuu HH:mm:ss" ) ;
LocalDateTime ldt = LocalDateTime.parse( input , f ) ;
ldt.toString(): 2011-02-04T20:27:05
Tip: Where possible, use the standard ISO 8601 formats when exchanging date-time values as text rather than format seen here. Conveniently, the java.time classes use the standard formats when parsing/generating strings.
The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.
Where to obtain the java.time classes?
The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time. You may find some useful classes here such as Interval, YearWeek, YearQuarter, and more.
You need a DateTimeFormatter appropriate to the format you're using. Take a look at the docs for instructions on how to build one.
Off the cuff, I think you need format = DateTimeFormat.forPattern("M/d/y H:m:s")
An simple method :
public static DateTime transfStringToDateTime(String dateParam, Session session) throws NotesException {
DateTime dateRetour;
dateRetour = session.createDateTime(dateParam);
return dateRetour;
}
There are two ways this could be achieved.
DateTimeFormat
DateTimeFormat.forPattern("dd/MM/yyyy HH:mm:ss").parseDateTime("04/02/2011 20:27:05");
SimpleDateFormat
String dateValue = "04/02/2011 20:27:05";
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss"); // 04/02/2011 20:27:05
Date date = sdf.parse(dateValue); // returns date object
System.out.println(date); // outputs: Fri Feb 04 20:27:05 IST 2011
