Parse datetime from string

Asked Jun 24 '20 at 06:37

Active Jun 24 '20 at 12:13

Viewed 81 times

I am trying to parse a date value that I read from another file. The format of the string is:

str := 2019-04-29 11:16:06.699920+0900
layout := "2006-01-02 15:04:05.000000Z"

t, err := time.Parse(layout, str)
// handle error

I get an error saying that +0900 cannot be parsed as Z. I tried using the following layout as well:

layout := "2006-01-02 15:04:05.000000+0000"

I can parse the datetime if I replace +0900 with Z but I don't want to lose the timezone. How can I parse the date of such format, keeping the timezone intact? Thanks.

EDIT: Parsing date string in Go has a good discussion on the layout used but doesn't address the alternatives to using Z that I needed.

Replacing Z with -0700 did the job.

edited Jun 24 '20 at 12:13

asked Jun 24 '20 at 06:37

su619

1

Does this answer your question? [Parsing date string in Go](https://stackoverflow.com/questions/25845172/parsing-date-string-in-go) – user743414 Jun 24 '20 at 06:44
Use `-0700` instead of `Z` in layout – Eklavya Jun 24 '20 at 07:15
-0700 did the job. Thanks @Eklavya! – su619 Jun 24 '20 at 07:51
@user743414 I felt that question and the answers talked about why we need to use a certain date for the layout. I understood that, but I couldn't find how to extract timezones using the layout they discussed. – su619 Jun 24 '20 at 07:52
last line says **Replacing Z with -0700 did the job.** , You mean the issue is solved ? – Arun Jun 24 '20 at 14:19
Yes, the issue is solved. – su619 Jun 25 '20 at 16:13

Parse datetime from string

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