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So basically I have a QR code generator in the app, I already implemented a feature generating it with url, such as domain.com/userid?=111. So, now I want QR code scanner to scan it and get only the id part of the user out of it, like it scanned the url example provided above, and then I just want to get '111' part to process. How can I implement it?

JideGuru
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massalini
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  • Shouldn't your url be `domain.com?userid=111` instead of `domain.com/userid?=111` – JideGuru Jun 24 '20 at 12:38
  • @JideGuru, no it should be `domain.com/?userid=111`, read more here: https://stackoverflow.com/a/1617074/1204153 – Andy Jun 24 '20 at 14:53
  • Ignore my comment, both should work and I don't want to start a debate about it like on that thread :) Either way, we can both agree OP's URI is wrong. – Andy Jun 24 '20 at 14:55

2 Answers2

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Use Uri queryParametersAll:

Uri url = Uri.parse('https://www.example.com/?userid=111');
print(url.queryParametersAll['userid'][0]);
JideGuru
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You can use substring method to get the part of it.

// Dart 2.6.1 

main() {
  String str = "domain.com/userid?=111";
  print(str.substring(str.indexOf("=")+1));
}
Ketan Ramteke
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