PYTHON - Break out of while loop when user enters a particular value

Question

So I require to run a certain set of functions as given in the if statement and I want this code to keep on asking the user to enter the required conditions as given below until it enters 1(or 0) and the loop breaks.

d = 0
id d==0:
    
while (d!=1):

text = input("Enter: ").lower()

if text=='t':
    function1()
elif text =='i':
    function2()
else :
    print("Enter a valid input")
    
d=input("want to run again enter 0 for yes and 1 for no" )          


enter code here

Please update the indentation of your code. Python is very sensitive to indentation, as are python programmers. — quamrana, Jun 25 '20 at 13:36

score 0 · Accepted Answer · edited Jun 25 '20 at 15:02

0

while True:
    a= input("want to run again enter 0 for yes and 1 for no" )
    if a=='0':
        text = input("Enter: ").lower()

        if text=='t':
            function1()
        elif text =='i':
            function2()
        else :
            print("Enter a valid input")
    elif a=="1":
        break
    else:
        print("Enter either 0/1")

edited Jun 25 '20 at 15:02

Umer Rana

148
6

answered Jun 25 '20 at 13:39

JaniniRami

493
3
11

PYTHON - Break out of while loop when user enters a particular value

1 Answers1