Regex to extract string between third and fourth underscore

Asked Jun 25 '20 at 18:39

Active Jun 25 '20 at 18:39

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How would I use regex to extract the string between the third and fourth underscore in the following example:

123456-AB_ABC_ABC123_Extract This_ABCDEFG

I tried

^(?:[^_]+_){3}([^_]+)

But it seems to return all of the characters up to the fourth underscore instead of starting after the third underscore like I imagined. What'd I miss there?

Thanks!

asked Jun 25 '20 at 18:39

user3716205

Split by `_` and get 3rd element from resulting array. – anubhava Jun 25 '20 at 18:40
Access the Group 1 value. – Wiktor Stribiżew Jun 25 '20 at 18:46
1

to begin with yuio use this regxer `^(?:([^_]+)_){4}` https://regex101.com/r/nOgKoE/1 – Jun 25 '20 at 20:01
Good one, @Edward. Alternatively, yuio could use the following regxer (which contains no capture groups) to match the desired text: `(?<=^(?:[^_\n]*_){3})[^_\n]*(?=_)`. [ref](https://regex101.com/r/0kiAkj/1/). Readers: this makes use of the fact that Javascript's regex engine is one of the few that support *variable-length* lookbehinds. – Cary Swoveland Jun 25 '20 at 22:23
@anubhava ... note exactly right ... it is the 4th element but the array index is `3`. – Peter Seliger Jun 26 '20 at 13:40
@PeterSeliger: `arr[3]` is actually 4th element and that's what I meant – anubhava Jun 26 '20 at 13:45
split by `^|_` then arr[4] – Jun 26 '20 at 20:02

Regex to extract string between third and fourth underscore

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