I want to exclude starting point from a array in python using numpy. How I can execute? For example I want to exclude 0, but want to continue from the very next real number(i.e want to run from greater than 0) following code x=np.linspace(0,2,10)
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Moslem Uddin
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Please, share your codes and errors here. Also, explain more what you want. – Hamed Baziyad Jun 26 '20 at 12:19
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To exclude 0 use `np.linspace(0,2,11)[1:]`. To exclude both 0 and 2 use `np.linspace(0,2,12)[1:-1]`. – Michael H. Jan 26 '22 at 22:35
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A supplement： `np.linspace(2, 0, 10, endpoint=False)` – Sean.H Dec 05 '22 at 10:20
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x=np.linspace(0,2,10)[1:] #remove the first element by indexing
print(x)
[0.22222222 0.44444444 0.66666667 0.88888889 1.11111111 1.33333333
1.55555556 1.77777778 2. ]
Bernad Peter
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Kind of an old question but I thought I'll share my solution to the problem.
Assuming you want to get an array
[0.2, 0.4, 0.6, 0.8, 1.0, 1.2, 1.4, 1.6, 1.8, 2.]
you can make use of the endpoint option in np.linspace() and reverse the direction:
x = np.linspace(2, 0, 10, endpoint=False)[::-1]
the [::-1] reverses the array so that it ends up being in the desired sequence.
HaddiWammi
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