I have the below dataframe .
scala> df.show
+---+------+---+
| M|Amount| Id|
+---+------+---+
| 1| 5| 1|
| 1| 10| 2|
| 1| 15| 3|
| 1| 20| 4|
| 1| 25| 5|
| 1| 30| 6|
| 2| 2| 1|
| 2| 4| 2|
| 2| 6| 3|
| 2| 8| 4|
| 2| 10| 5|
| 2| 12| 6|
| 3| 1| 1|
| 3| 2| 2|
| 3| 3| 3|
| 3| 4| 4|
| 3| 5| 5|
| 3| 6| 6|
+---+------+---+
created by
val df=Seq( (1,5,1), (1,10,2), (1,15,3), (1,20,4), (1,25,5), (1,30,6), (2,2,1), (2,4,2), (2,6,3), (2,8,4), (2,10,5), (2,12,6), (3,1,1), (3,2,2), (3,3,3), (3,4,4), (3,5,5), (3,6,6) ).toDF("M","Amount","Id")
Here I have a base column M and is ranked as ID based on Amount. I am trying to compute the percentile keeping M as a group but for every last three values of Amount.
I am Using the below code to find the percentile for a group. But how can I target the last three values. ?
df.withColumn("percentile",percentile_approx(col("Amount") ,lit(.5)) over Window.partitionBy("M"))
Expected Output
+---+------+---+-----------------------------------+
| M|Amount| Id| percentile |
+---+------+---+-----------------------------------+
| 1| 5| 1| percentile(Amount) whose (Id-1) |
| 1| 10| 2| percentile(Amount) whose (Id-1,2) |
| 1| 15| 3| percentile(Amount) whose (Id-1,3) |
| 1| 20| 4| percentile(Amount) whose (Id-2,4) |
| 1| 25| 5| percentile(Amount) whose (Id-3,5) |
| 1| 30| 6| percentile(Amount) whose (Id-4,6) |
| 2| 2| 1| percentile(Amount) whose (Id-1) |
| 2| 4| 2| percentile(Amount) whose (Id-1,2) |
| 2| 6| 3| percentile(Amount) whose (Id-1,3) |
| 2| 8| 4| percentile(Amount) whose (Id-2,4) |
| 2| 10| 5| percentile(Amount) whose (Id-3,5) |
| 2| 12| 6| percentile(Amount) whose (Id-4,6) |
| 3| 1| 1| percentile(Amount) whose (Id-1) |
| 3| 2| 2| percentile(Amount) whose (Id-1,2) |
| 3| 3| 3| percentile(Amount) whose (Id-1,3) |
| 3| 4| 4| percentile(Amount) whose (Id-2,4) |
| 3| 5| 5| percentile(Amount) whose (Id-3,5) |
| 3| 6| 6| percentile(Amount) whose (Id-4,6) |
+---+------+---+----------------------------------+
This seems to be little bit tricky to me as I am still learning spark.Expecting answers from enthusiasts here.