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I want to crop a FITS image area between two circles. For example, I want to crop out an area in the FITS image between circles of radii of R1 and R2. How do I go about it?

  • By "crop" do you mean mask, as in an [aperture](https://photutils.readthedocs.io/en/stable/aperture.html)? – Iguananaut Jul 01 '20 at 11:25
  • I'm working with FITS images, where I've to estimate the counts in an area between two concentric circles of different radii. Can you help me? – SlightDecoy Jul 02 '20 at 12:04

1 Answers1

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You will probably find what you're looking for in the regions package: https://astropy-regions.readthedocs.io/en/latest/

It can create regions with pixel or sky coordinates, combine them, and create pixel masks:

In [1]: from regions import CirclePixelRegion, PixCoord                                                  

In [2]: c1 = CirclePixelRegion(center=PixCoord(6, 6), radius=3)                                          

In [3]: c2 = CirclePixelRegion(center=PixCoord(9, 9), radius=3)                                          

In [4]: (c1 & c2).to_mask().data                                                                         
Out[4]: 
array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
       [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
       [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
       [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
       [0, 0, 0, 0, 1, 1, 0, 0, 0, 0],
       [0, 0, 0, 0, 1, 1, 0, 0, 0, 0],
       [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
       [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
       [0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
       [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]])

In [5]: (c1 | c2).to_mask().data                                                                         
Out[5]: 
array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
       [0, 0, 0, 0, 1, 1, 1, 1, 1, 0],
       [0, 0, 0, 0, 1, 1, 1, 1, 1, 0],
       [0, 0, 0, 0, 1, 1, 1, 1, 1, 0],
       [0, 1, 1, 1, 1, 1, 1, 1, 1, 0],
       [0, 1, 1, 1, 1, 1, 1, 1, 1, 0],
       [0, 1, 1, 1, 1, 1, 0, 0, 0, 0],
       [0, 1, 1, 1, 1, 1, 0, 0, 0, 0],
       [0, 1, 1, 1, 1, 1, 0, 0, 0, 0],
       [0, 0, 0, 0, 0, 0, 0, 0, 0, 0]])
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