Python convert date format

Question

Given a string like this:

2020-08-14

How do I convert it to:

14 August 2020

Using python 3?

Read up on [datetime — Basic date and time types](https://docs.python.org/3/library/datetime.html?highlight=datetime) — stovfl, Jul 01 '20 at 13:00

score 4 · Answer 1 · answered Jul 01 '20 at 11:09

You can use the datetime module for reformatting date strings. Using strptime you can read from a string into a datetime object, then using strftime you can convert back to a string with a different format.

>>> from datetime import datetime
>>> d = datetime.strptime('2020-08-14', '%Y-%m-%d')
>>> d
datetime.datetime(2020, 8, 14, 0, 0)
>>> d.strftime('%d %B %Y')
'14 August 2020'

score 2 · Accepted Answer · answered Jul 01 '20 at 11:28

2

An alternative approach using pandas function below:

import pandas as pd
d = pd.to_datetime('2020-08-14')
d.strftime('%d %B %Y')
Out[11]: '14 August 2020'

answered Jul 01 '20 at 11:28

RunTheGauntlet

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1
4
15

score -1 · Answer 3 · answered Jul 01 '20 at 12:53

monthDict = {
'01' : 'January',
'02' : 'February',
'03' : 'March',
'04' : 'April',
'05' : 'May',
'06' : 'June',
'07' : 'July',
'08' : 'August',
'09' : 'September',
'10' : 'October',
'11' : 'November',
'12' : 'December'
}
readDate = input('Pleaes enter the date in the yyyy-mm-dd format: ')
day = readDate.split('-')[2]
month = readDate.split('-')[1]
year = readDate.split('-')[0]
print('Printing in the dd month year format: ', day, monthDict[month], year)

Python convert date format

3 Answers3

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