How to create dynamic char array with dynamic row's and column's size

Question

I've attempted to create a dynamic char array:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void push(int *rows, char **arr, char *value) {
    int colum = strlen(value);
    arr = malloc(*rows * sizeof(char *));
    arr[*rows] = malloc(colum * sizeof(char));
    arr[*rows] = value;
    printf("%s\n", arr[*rows]);

    // increment rows variable
    (*rows)++;
}

int main() {
    int rows = 0;
    char **arr = NULL;
    arr = malloc(sizeof(char) * sizeof(char *));
    push(&rows, arr, "test");

    printf("%s", arr[0]);
}

This outputs:

test
(null)

Indicating that the value test is not being stored into the **arr pointer array correctly.

I want to print the contents of **arr, what am I doing wrong?