Value types in java

Question

public class MyClass {
public static void main(String[ ] args) {
    int x = 5;
    addOneTo(x);
    System.out.println(x);       
}

static int addOneTo(int num) {
    return  num + 1;
}

}

I expected it to return 6!! But it do return 5

Why

Java is 'pass by value' -- nothing you do to a parameter affects the variable which was used by the caller as a parameter. You are discarding the return value of addToOne. — tgdavies, Jul 04 '20 at 06:34

score 0 · Answer 1 · answered Jul 04 '20 at 07:00

0

You have just added 1 to the int variable and returning it and you didnt assign it back to int variable in main method.

answered Jul 04 '20 at 07:00

sai

109
2
13

score 0 · Answer 2 · answered Jul 04 '20 at 07:04

0

Check this one

public class MyClass {
public static void main(String[ ] args) {
    int x = 5;
    System.out.println(addOneTo(x));       
}

static int addOneTo(int num) {
    return  num + 1;
}

answered Jul 04 '20 at 07:04

Thiluxan

177
4
13

Value types in java

2 Answers2