Trying to run simple script at python prompt but getting an error

Question

Trying to run simple python file in python prompt but giving an error:

content of test.py

print("Trying to print this using .py file on anaconda prompt")

Running file from python prompt

(base) C:\Users\acharbha>python
Python 3.6.5 |Anaconda, Inc.| (default, Mar 29 2018, 13:32:41) [MSC v.1900 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> python C:\Users\acharbha\Documents\python\test.py
  File "<stdin>", line 1
    python C:\Users\acharbha\Documents\python\test.py
           ^
SyntaxError: invalid syntax
>>>

You are trying to run a shell/cmd command inside of the python IDLE. — jordanm, Jul 06 '20 at 16:10
@jordanm Just curious, how can you tell it's IDLE? It looks like any other REPL to me. — wjandrea, Jul 06 '20 at 16:22
You are trying to run a shell/cmd command inside of the python console. — martineau, Jul 06 '20 at 16:33

score 0 · Answer 1 · answered Jul 06 '20 at 16:15

0

You are trying to run it within the python interpreter. So just exit that and run the command on the terminal.

answered Jul 06 '20 at 16:15

Sai Sreenivas

1,690
1
7
16

score 0 · Accepted Answer · edited Jul 06 '20 at 16:21

0

To execute in shell: python test.py

To execute inside the interpreter: exec(open("test.py").read())

This should help: How to execute a file within the python interpreter?

edited Jul 06 '20 at 16:21

wjandrea

28,235
9
60
81

answered Jul 06 '20 at 16:16

undefined

31
1

Trying to run simple script at python prompt but getting an error

2 Answers2