Extract a single (unsigned) integer from a string

Question

I want to extract the digits from a string that contains numbers and letters like:

"In My Cart : 11 items"

I want to extract the number 11.

Answer 1

If you just want to filter everything other than the numbers out, the easiest is to use filter_var:

$str = 'In My Cart : 11 items';
$int = (int) filter_var($str, FILTER_SANITIZE_NUMBER_INT);

Answer 2

$str = 'In My Cart : 11 12 items';
preg_match_all('!\d+!', $str, $matches);
print_r($matches);

Answer 3

preg_replace('/[^0-9]/', '', $string);

This should do better job!...

Answer 4

Using preg_replace:

$str = '(111) 111-1111';
$str = preg_replace('/\D/', '', $str);
echo $str;

Output: 1111111111

Answer 5

For floating numbers,

preg_match_all('!\d+\.?\d+!', $string ,$match);

Thanks for pointing out the mistake. @mickmackusa

Answer 6

I do not own the credit for this, but I just have to share it. This regex will get numbers from a string, including decimal points/places, as well as commas:

/((?:[0-9]+,)*[0-9]+(?:\.[0-9]+)?)/

Cited from here:
php - regex - how to extract a number with decimal (dot and comma) from a string (e.g. 1,120.01)?

Answer 7

You can use preg_match:

$s = "In My Cart : 11 items";
preg_match("|\d+|", $s, $m);
var_dump($m);

Answer 8

Using preg_replace

$str = 'In My Cart : 11 12 items';
$str = preg_replace('/\D/', '', $str);
echo $str;

Answer 9

The top resource-friendly solutions

<?php
    var $string = "In My Cart : 11 items";
?>

1. Fastest: filter_var — Filters a variable with a specified filter

<?php
    filter_var($string, FILTER_SANITIZE_NUMBER_INT); // string(2) "11"
?>

2. Almost the fastest: str_replace — Replace all occurrences of the search string with the replacement string

<?php
    str_replace(array('In My Cart : ',' item', 's'),"", $string); // string(2) "11"
?>

3. Fast enough: preg_replace — Perform a regular expression search and replace

<?php
    preg_replace("/[^0-9]/","",$string); // string(2) "11"
?>

However

• the simplicity of str_replace cause speed, but even limited use cases
• preg_replace is much more versatile than str_replace or filter_var
• instead is possible to use a function to specify what to replace using preg_replace_callback
• with preg_replace_callback can do multiple replacements in one call
• filter_var limited in sanitation options

Answer 10

$value = '25%';

Or

$value = '25.025$';

Or

$value = 'I am numeric 25';
$onlyNumeric = filter_var($value, FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION);

This will return only the numeric value

Answer 11

You can use following function:

function extract_numbers($string)
{
   preg_match_all('/([\d]+)/', $string, $match);

   return $match[0];
}

Answer 12

Since there is only 1 numeric value to isolate in your string, I would endorse and personally use filter_var() with FILTER_SANITIZE_NUMBER_INT.

echo filter_var($string, FILTER_SANITIZE_NUMBER_INT);

A whackier technique which works because there is only 1 numeric value AND the only characters that come before the integer are letters, colons, or spaces is to use ltrim() with a character mask then cast the remaining string as an integer.

Demo

$string = "In My Cart : 11 items";
echo (int)ltrim($string, 'A..z: ');
// 11

---

If for some reason there was more than one integer value and you wanted to grab the first one, then regex would be a direct technique.

Demo

echo preg_match('/\d+/', $string, $m) ? $m[0] : '';

---

sscanf() is rather handy if you need to explicitly cast the numeric string as an integer (or float). If it is possible/unknown for the integer value to occur at the start of the string, then prepend a non-numeric character to the input string before scanning it. The following technique matches leading non-digits (and ignores them with * after the %), then matches the first occurring sequence of digits and casts the returned substring as an integer.

Demo

var_dump(sscanf(' ' . $string, '%*[^0-9]%d')[0]);

To adapt this technique to extract a float value, just change the d to f. For more information on the (currently undocumented) assignment suppression feature of sscanf(), see this post.

Answer 13

preg_match_all('!\d+!', $some_string, $matches);
$string_of_numbers = implode(' ', $matches[0]);

The first argument in implode in this specific case says "separate each element in matches[0] with a single space." Implode will not put a space (or whatever your first argument is) before the first number or after the last number.

Something else to note is $matches[0] is where the array of matches (that match this regular expression) found are stored.

For further clarification on what the other indexes in the array are for see: http://php.net/manual/en/function.preg-match-all.php

Answer 14

try this,use preg_replace

$string = "Hello! 123 test this? 456. done? 100%";
$int = intval(preg_replace('/[^0-9]+/', '', $string), 10);
echo $int;

DEMO

Answer 15

we can extract int from it like

$string = 'In My Car_Price : 50660.00';

echo intval(preg_replace('/[^0-9.]/','',$string));  # without number format   output: 50660
echo number_format(intval(preg_replace('/[^0-9.]/','',$string)));  # with number format  output :50,660

demo : http://sandbox.onlinephpfunctions.com/code/82d58b5983e85a0022a99882c7d0de90825aa398

Answer 16

Follow this step it will convert string to number

$value = '$0025.123';
$onlyNumeric = filter_var($value, FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION);
settype($onlyNumeric,"float");

$result=($onlyNumeric+100);
echo $result;

Another way to do it :

$res = preg_replace("/[^0-9.]/", "", "$15645623.095605659");

Answer 17

other way(unicode string even):

$res = array();
$str = 'test 1234 555 2.7 string ..... 2.2 3.3';
$str = preg_replace("/[^0-9\.]/", " ", $str);
$str = trim(preg_replace('/\s+/u', ' ', $str));
$arr = explode(' ', $str);
for ($i = 0; $i < count($arr); $i++) {
    if (is_numeric($arr[$i])) {
        $res[] = $arr[$i];
    }
}
print_r($res); //Array ( [0] => 1234 [1] => 555 [2] => 2.7 [3] => 2.2 [4] => 3.3 ) 

Answer 18

An alternative solution with sscanf:

$str = "In My Cart : 11 items";
list($count) = sscanf($str, 'In My Cart : %s items');

Answer 19

If you don't know which format the number is? int or floating, then use this :

$string = '$125.22';

$string2 = '$125';

preg_match_all('/(\d+.?\d+)/',$string,$matches); // $matches[1] = 125.22

preg_match_all('/(\d+.?\d+)/',$string2,$matches); // $matches[1] = 125

Answer 20

Depending on your use case, this might also be an option:

$str = 'In My Cart : 11 items';
$num = '';

for ($i = 0; $i < strlen($str); $i++) {

    if (is_numeric($str[$i])) {
        $num .= $str[$i];
    }
}

echo $num; // 11

Though I'd agree a regex or filter_var() would be more useful in the stated case.

Answer 21

for utf8 str:

function unicodeStrDigits($str) {
    $arr = array();
    $sub = '';
    for ($i = 0; $i < strlen($str); $i++) { 
        if (is_numeric($str[$i])) {
            $sub .= $str[$i];
            continue;
        } else {
            if ($sub) {
                array_push($arr, $sub);
                $sub = '';
            }
        }
    }

    if ($sub) {
        array_push($arr, $sub); 
    }

    return $arr;
}

Answer 22

This functions will also handle the floating numbers

$str = "Doughnuts, 4; doughnuts holes, 0.08; glue, 3.4";
$str = preg_replace('/[^0-9\.]/','-', $str);
$str = preg_replace('/(\-+)(\.\.+)/','-', $str);
$str = trim($str, '-');
$arr = explode('-', $str);

Answer 23

This script creates a file at first , write numbers to a line and changes to a next line if gets a character other than number. At last, again it sorts out the numbers to a list.

string1 = "hello my name 12 is after 198765436281094and14 and 124de"
f= open("created_file.txt","w+")
for a in string1:
    if a in ['1','2','3','4','5','6','7','8','9','0']:
        f.write(a)
    else:
        f.write("\n" +a+ "\n")
f.close()


#desired_numbers=[x for x in open("created_file.txt")]

#print(desired_numbers)

k=open("created_file.txt","r")
desired_numbers=[]
for x in k:
    l=x.rstrip()
    print(len(l))
    if len(l)==15:
        desired_numbers.append(l)


#desired_numbers=[x for x in k if len(x)==16]
print(desired_numbers)