How to sort a list of tuples, by the second tuple element?

Question

I have a list like this:

[('TIPE_ORG', 'Corea'), ('TIPE_ORG', 'United Kingdom'), ('TIPE_ORG', 'Russia'), ('TIPE_ORG', 'Germany'),('TIPE_PER', 'Pepe Martínez')]

I want it to be sorted by text length from largest to smallest of the second parameter Let it be like this:

[('TIPE_ORG', 'United Kingdom'),('TIPE_PER', 'Pepe Martínez'), ('TIPE_ORG', 'Germany'), ('TIPE_ORG', 'Russia'),('TIPE_ORG', 'Corea')]

I have tried to do this, but having two parameters does not order it for the second, but for the first TIPE_ORG:

x.sort(key=len, reverse=True)

Does this answer your question? https://stackoverflow.com/questions/3121979/how-to-sort-a-list-tuple-of-lists-tuples-by-the-element-at-a-given-index — Ronald, Jul 08 '20 at 10:17
`key=callback_function`. lambda is an anonymous function. Here you can learn about lambda functions: https://realpython.com/python-lambda/ — Ronald, Jul 08 '20 at 10:24
Does this answer your question? [How to sort a list/tuple of lists/tuples by the element at a given index?](https://stackoverflow.com/questions/3121979/how-to-sort-a-list-tuple-of-lists-tuples-by-the-element-at-a-given-index) — Daniel Morell, Jul 08 '20 at 10:51

Adam · Answer 1 · 2020-07-08T10:29:53.370

2

this can be done by sorting inplace with sort method or sorting and return anew sorted list with sorted method. for the equality decition, we use lambda function. see below:

my_list=[('TIPE_ORG', 'Corea'), ('TIPE_ORG', 'United Kingdom'),('TIPE_PER', 'Pepe Martínez')]

my_new_list = sorted(my_list, key=lambda this_tup:len(this_tup[1]), reverse=True)

or

sort(my_list, key=lambda this_tup:len(this_tup[1]), reverse=True)

you can refer to this link they have good examples about lambda expressions and how to use it.

lambda

edited Jul 08 '20 at 10:29

answered Jul 08 '20 at 10:23

Adam

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Apart from the fact that this answer sorts alphabetically and not on length, it is discouraged to provide an answer if the question already has an answer elsewhere. – Ronald Jul 08 '20 at 10:26
i am fixing my answer. patience please. i dont know what you talking about @Ronald. now you can remove the down vote. – Adam Jul 08 '20 at 10:30

score 2 · Accepted Answer · answered Jul 08 '20 at 10:26

You can use sorted method with a lambda function as below.

lst=[('TIPE_ORG', 'Corea'), ('TIPE_ORG', 'United Kingdom'), ('TIPE_ORG', 'Russia'), ('TIPE_ORG', 'Germany'),('TIPE_PER', 'Pepe Martínez')]

sorted(lst,key=lambda key:len((key[1])),reverse=True)

Output will be

[('TIPE_ORG', 'United Kingdom'),
('TIPE_PER', 'Pepe Martínez'),
('TIPE_ORG', 'Germany'),
('TIPE_ORG', 'Russia'),
('TIPE_ORG', 'Corea')]

How to sort a list of tuples, by the second tuple element?

2 Answers2