nested if statement inside for loop python

Question

I'm trying to do a nested if statement

for x in listsent:
    print(x)
    
    z = input()
    if z == 1:
        tag = "O"
        q = input()
        if q == 1:
            pos = "Q"
        elif q == 2:

            

    elif z == 2:
        tag = "Q"
        q = input()
        if q == 1:
            pos = "O"
        elif q == 2:

but when when I enter 1 in the first IF statement it takes me to the next item in the for loop instead of taking me to the second if statement

Spend the time to learn how to use a debugger, and step through your code line by line, and watch what your variables are doing at each stage. You will find it altogether easier to find and solve problems with your code once you know how to do this. — Jack Aidley, Jul 10 '20 at 08:26
Is this your real code? It looks invalid because there is nothing following the `elif q == 2:` — quamrana, Jul 10 '20 at 08:27

score 1 · Answer 1 · answered Jul 10 '20 at 08:40

1

Input returns a string, not an integer. To convert string to integer, use z = int(input()) and q = int(input()) wherever required

answered Jul 10 '20 at 08:40

Kushagra Saxena

11
1
3

Or even better - don't convert it and just do `q=="1"` instead - one operation less, yet same output ;) – Grzegorz Skibinski Jul 10 '20 at 08:44

nested if statement inside for loop python

1 Answers1