invalid literal error when converting hex to int python

Question

Am trying to convert this hex value to int and I get invalid litrel error in python 3.7

>>> int('1.222664064E9', 16)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 16: '1.222664064E9'

The `E` does not mean that it's a hex value but 1.22...*10^9 — tobias_k, Jul 10 '20 at 18:14
I was wrong, it was a float value, Thanks for pointing it out — SUN, Jul 10 '20 at 18:20
Does this answer your question? [ValueError: invalid literal for int() with base 10: ''](https://stackoverflow.com/questions/1841565/valueerror-invalid-literal-for-int-with-base-10) — AMC, Jul 10 '20 at 18:22

wjandrea · Accepted Answer · 2020-07-10T18:30:20.107

2

Use float.fromhex:

>>> float.fromhex('1.222664064E9')
1.1333982959172886
>>> int(_)
1

Although are you sure it's hex? It looks like a float in exponent notation, where E9 stands for * 10 ** 9:

>>> float('1.222664064E9')
1222664064.0
>>> int(_)
1222664064

edited Jul 10 '20 at 18:30

answered Jul 10 '20 at 18:14

wjandrea

28,235
9
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I am 0.99E2% sure that it's exponential notation... maybe swap the two parts of the answer? – tobias_k Jul 10 '20 at 18:18
@tobias_k I prefer it as-is. OP's saying it's hex, so I'm taking their word for it, but offering my reservation. – wjandrea Jul 10 '20 at 18:19
@tobias_k But now you're vindicated, lol :) – wjandrea Jul 10 '20 at 18:21

invalid literal error when converting hex to int python

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