import re
string='probability is 1'
string2='probability is 1.03'
def FindProb(string):
pattern=re.compile('[0-9]')
result=pattern.search(string)
result=result.span()[0]
prob=string[result:]
return(prob)
print(FindProb(string2))
Ok, so.
This is using the regular expression (aka Regex aka re) library
It basically sets up a pattern and then searches for it in a string.
This function takes in a string and finds the first number in the string, then returns the variable prob which would be the string from the first number to the end.
If you need to find the probability multiple times then this might do it:
import re
string='probability is 1'
string2='probability is 1.03 blah blah bllah probablity is 0.2 ugggggggggggggggg probablity is 1.0'
def FindProb(string):
amount=string.count('.')
prob=0
for i in range(amount):
pattern=re.compile('[0-9]+[.][0-9]+')
result=pattern.search(string)
start=result.span()[0]
end=result.span()[1]
prob+=float(string[start:end])
string=string[end:]
return(prob)
print(FindProb(string2))
The caveat to this is that everything has to have a period so 1 would have to be 1.0 but that shouldn't be too much of a problem. If it is, let me know and I will try to find a way