I want to sort a list filled with lists by their 0th index.
In Python, this would look like
l = [[1, 0], [5, 1], [6, 2], [3, 2]
l.sort(key=lambda x: x[0])
#l is now [[1, 0], [3, 2], [5, 1], [6, 1]]
What would this look like in Javascript?
Asked
Active
Viewed 44 times
-5
Lovesh Dongre
- 1,294
- 8
- 23
-
1`l.sort((a, b) => a[0] - b[0])` – CRice Jul 13 '20 at 20:37
-
There is no direct comparison method in javascript, but you can define a custom sort function to manually compare the first element of each set – Andy Ray Jul 13 '20 at 20:37
2 Answers
1
Array sort method does the same job:
const arr = [[1, 0], [5, 1], [6, 2], [3, 2]];
arr.sort((a,b) => a[0] - b[0]);
console.log(arr);
Jumshud
- 1,385
- 1
- 13
- 19
0
You could create a function which takes a function fro getting the value for sorting.
let l = [[1, 0], [5, 1], [6, 2], [3, 2]],
fn = x => x[0],
sort = fn => (a, b) => fn(a) - fn(b);
l.sort(sort(fn));
l.forEach(a => console.log(...a));
Nina Scholz
- 376,160
- 25
- 347
- 392