dictionary with list comprehension

Question

an exercise requires me to write a list comprehension (where the keys should be divisible by 2 and in a range 0-10; the value for each key should be equal to the square of the key) that returns the following output.

my_dict = { (write code here) for num in (write code here) if (write code here)}

I have tried the following code but I am obviously making some mistakes.

my_dict = {num**2 for num in range(0,10) if float(num/2)==False}
my_dict

Could any of you help me understand how it should be done?

thank you very much

Hi please edit the results generated by your code into your question as text (i.e. not as an image). — DisappointedByUnaccountableMod, Jul 14 '20 at 12:43
`if float(num/2)==False` Unless `num` is `0`, `num/2` will never be `0`, hence `float(num/2)==False` will never be `True` — DeepSpace, Jul 14 '20 at 12:43
`float(num/2)==False` is **not** how you check for parity. See https://stackoverflow.com/questions/13636640/python-checking-odd-even-numbers-and-changing-outputs-on-number-size — DeepSpace, Jul 14 '20 at 12:44
[PEP-274](https://www.python.org/dev/peps/pep-0274/#:~:text=This%20PEP%20proposes%20a%20similar,objects%20instead%20of%20list%20objects) — Sayandip Dutta, Jul 14 '20 at 12:44
Note that you want to use `num: num**2` in the first spot. What you have currently is a `set` comprehension not a `dict` comprehension. — 0x5453, Jul 14 '20 at 12:45

score 0 · Accepted Answer · answered Jul 14 '20 at 12:45

0

Try

my_dict = {num : num ** 2 for num in range(10) if num % 2 == 0}
print(my_dict)

Output

{0: 0, 2: 4, 4: 16, 6: 36, 8: 64}

answered Jul 14 '20 at 12:45

Balaji Ambresh

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dictionary with list comprehension

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