I have a Firestore collection named 'users'
and has many documents by the name of each user.
I want to retrieve list of 25 users at a time in alphabetical order and this is what I tried:
const allUsersRef = admin.firestore().collection('users').orderBy('name').offset(0).limit(25)
allUsersRef.get().then((top25Users) => {
let usersList = '``` << Users LIST >>\n'
if (!top25Users.empty) {
top25Users.forEach(eachUser => {
usersList = usersList + `\n${eachUser.data().name} \n${eachUser.data().id}`
})
console.log(usersList)
return
} else {
message.channel.send('Looks like we have no users at the moment!')
return
}
}).catch((error) => {
console.log(error)
return
})
This way I can get the top 25 users easily! But what if I want the next 25? This is a Discord Bot and not an Android Application where I can add a button [view more] and then continue the results query.start()
as shown in this firebase video
I can use OFFSET
but the number of users is large so using offset(500)
won't be affordable :'(
Also I need to fetch users in alphabetical order and when new users register, the order changes.
TL,DR: If I had a list of my users in alphabetical order, how do I get users from 126th position to 150th position on the list which is sort of page 5 for my 25/page query! and without using offset because that just uses more resources!
I had this in firebase realtime database first but then I needed some more advanced querying so I have migrated here :)
Database Struture: Just a single collection named USERS and documents named as username in it.
PS:
const startAtRes = await db.collection('cities')
.orderBy('population')
.startAt(1000000)
.get();
Using something like this ^ from Firebase Documentation is not possible because I won't be knowing from where to start from. As the list changes as new users Register!