Python: Get value from list of dictionary

Question

I have a list of dicts like this:

    [{'sftp_conn': 'conn_1', 'sftp_path': 'path_1'}, 
     {'sftp_conn': 'conn_2', 'sftp_path': 'path_2'}
    ]

I know how to fetch values from the list of values

I want to loop each in the list and assign values to the variables

  id =1   sftp_conn = 'conn_1' , sftp_path = 'path_1'

then next

  id=2  sftp_conn = 'conn_2' , sftp_path = 'path_2'

I have an Airflow code as below, so I want to iterate and pass the values to sftp_path and sftp_conn_id

    for count, sftp in enumerate(sftp_list):
                s3_to_sftp = S3ToSftpOperator(
                    task_id=f's3_to_sftp_{count}',
                    sftp_path=  ,
                    sftp_conn_id= ,
                    s3_conn_id=S3_CONN_ID,
                )

Its not separate , but like we have enumerate in list which gets 0 , 1 — Kar, Jul 14 '20 at 16:32
Why did you not write the code that does the loop and assigns the values to variables? — mkrieger1, Jul 14 '20 at 16:47
I was able to do for a list of values, honestly, I am trying with list of dict values — Kar, Jul 14 '20 at 16:50
See [this answer](https://stackoverflow.com/questions/21986194/how-to-pass-dictionary-items-as-function-arguments-in-python) — Sergey Dyshko, Jul 14 '20 at 16:53

score 1 · Accepted Answer · answered Jul 14 '20 at 16:56

You just need to enumerate over the list while passing start=1 to start counting from 1 instead of 0. Please let me know if this is not what you meant.

li = [{'sftp_conn': 'conn_1', 'sftp_path': 'path_1'},{'sftp_conn': 'conn_2', 'sftp_path': 'path_2'}]

for item in enumerate(li, start=1):
    taskID, sftp_conn, sftp_path = item[0], item[1]['sftp_conn'], item[1]['sftp_path']
    #print(taskID, sftp_conn, sftp_path)

When that print line is uncommented, this will be the output for above list:

1 conn_1 path_1
2 conn_2 path_2

Y4RD13 · Answer 2 · 2020-07-14T16:40:42.717

0

You can easily iterate over it and use values() dict method.

d = [{'sftp_conn': 'conn_1', 'sftp_path': 'path_1'}, 
    {'sftp_conn': 'conn_2', 'sftp_path': 'path_2'}
    ]
    
x = [(' '.join(i.values())).split(' ') for i in d]
v1, v2, v3, v4 = x[0][0], x[0][1], x[1][0], x[1][1]

edited Jul 14 '20 at 16:40

answered Jul 14 '20 at 16:33

Y4RD13

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I want to pass the values to the variable example ` sftp_conn = conn_1 `and `sftp_path = path_1` for first list then iterate to second list – Kar Jul 14 '20 at 16:39
great, Also I need to enumerate values as we have in list enumerate which gives 0 ,1 – Kar Jul 14 '20 at 16:43
@Kar I don't know If I'm understanding correctly, would you like to assign values to each dictionary? Or do you want to name each dictionary? – Y4RD13 Jul 14 '20 at 16:46
Updated the original question with detailed – Kar Jul 14 '20 at 16:49

Python: Get value from list of dictionary

2 Answers2