arrow function filter

Question

I wonder why is this udefinded:

const numbers2 = [45, 5, 9, 16, 25];

const myFunction1 = (numbers2) =>{numbers2.filter(number=>{return number>6})}; 

console.log("Soy filter con arrowFunction: " + myFunction1(numbers2)); // Soy filter con arrowFunction: undefined

with curly brackets, you need a `return` statement. or use without curlies. — Nina Scholz, Jul 15 '20 at 17:43
remove braces `{}`; change to `myFunction1 = numbers2 => numbers2.filter(...)`; or better `const greaterThan6 = nums => nums.filter(n => n > 6)` — Mulan, Jul 15 '20 at 17:50

score 1 · Answer 1 · edited Jul 15 '20 at 23:28

1

You having a missing return. See below in the code it is added.

const numbers2 = [45, 5, 9, 16, 25];

const myFunction1 = (numbers2) =>{
  return numbers2.filter(number=>{   // <===== missing return was here
    return number>6
  }
  )
};

console.log("Soy filter con arrowFunction: " + myFunction1(numbers2));

edited Jul 15 '20 at 23:28

Red

26,798
7
36
58

answered Jul 15 '20 at 17:48

Mohsen Alyafei

4,765
3
30
42

Nina Scholzt is right. Brackets were the issue. Delete them and will run perfectly. const numbers2 = [45, 5, 9, 16, 25]; const myFunction1 = (numbers2) => numbers2.filter(number=>{return number>6}); console.log("Soy filter con arrowFunction: " + myFunction1(numbers2)); – Andres Diaz Jul 16 '20 at 19:16

arrow function filter

1 Answers1