Tersest way to create an array of integers from 1..20 in JavaScript

Question

What would be the tersest way to create this array:

var x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10,
         11, 12, 13, 14, 15, 16, 17, 18, 19, 20];

For example, a for loop:

var x = [];
for (var i=1;i<=20;i++) {
  x.push(i);
}

Or a while loop:

var x = [], i = 1, endInt = 20;
while (i <= endInt) {
  x.push(i);
  i++;
}

Would there be other examples that would be terser -- in other words -- less code? I'm thinking of things like in Ruby where the equivalent code I believe would be as simple as 1..20. I'm not aware of syntax like that in JavaScript but I'm wondering if there are shorter ways to do that same thing.

UPDATE: I wasn't thinking of removing semicolons or var for answers in the question, but I have to admit the question implies that. I am more curious about algorithms than shaving bytes. Sorry if I was unclear! Also, making it into a function is simple enough, just slap function range(start, end) { /* guts here */ } around it and you're there. The question is are there novel approaches to the "guts."

Answer 1

Favorite method

Update Sep13,2015:

Just came up with this new method which works with browsers which support the ES6 standard:

> Array(5).fill().map((x,i)=>i)
[0, 1, 2, 3, 4]

Note the above does a tiny bit of extra work (fills with undefined) but is relatively minor vis-a-vis the speedup you can achieve by using a for loop, and if you forget the .fill you may be confused why your array is mysteriously [empty x 5]. You can encapsulate the above as a custom function, or alternatively use a somewhat more intended method:

> Array.from(Array(5),(x,i)=>i)
[0, 1, 2, 3, 4]

You can of course directly go from that into whatever you want to do, like python's list comprehensions e.g. [i**2 for i in range(5)]:

> Array.from(Array(5), (_,i)=> i**2)
[0, 1, 4, 9, 16]

... or if you want to get more complicated...:

> Array.from(Array(5), (_,i)=> {
    const R = /*some computation*/;
    return /*etc*/;
});

[edit May,2021]: theoretically tersest way of defining such a function nowadays is f=i=>i?[...f(i-1),i]:[], where you replace f with range1 or whatever the name is, but which would be very slow (quadratic complexity) due to intermediate structures so should never be used. f=i=>i?f(i-1)&&x.push(i)&&x:x=[] is linear complexity but relies on abuse of notation and is unreadable and pollutes global variables as well. But, since defining arrow functions (which don't bind but rather inherit this) is pretty terse nowadays, you could just wrap the above solution:

const range1 = n=> Array.from(Array(n), (_,i)=> i+i);
// range1(5)==[1, 2, 3, 4, 5]

Circumstantially, the tersest way to do a range(N), if you already have a list lying around of exactly that length N, is just to map it: e.g. rather than do Array.from(Array(myArr.length), (_,i)=> i**2), you would just do myArr.map((_,i)=> i**2). (This has no side-effect unless you want it to.)

---

everything below is historical:

After thinking about it a bit, this is the shortest implementation of the standard range(N) function in JavaScript I could come up with:

function range1(i){return i?range1(i-1).concat(i):[]}

Note: Do not use this in production; it's O(N^2)

Contrast with current top-voted answer:

function range1(i){var x=[];var i=1;while(x.push(i++)<i){};return x}

---

Example:

> range1(5)
[1, 2, 3, 4, 5]

---

This is like the poster child for recursion, though I was expecting it to be longer until I thought of ternary-if-statement, which brings it down to 42 necessary characters.

Note that the "standard" range function returning [start,end) can be written by doing .concat(i-1).

---

Update: Ooh, I discovered an incredibly short version with ugly imperative syntax by abusing for loops, reverse-ordering, the fact that assignments return a value: for(y=[],i=20;y[--i]=i;){} consisting of only 25 characters (though you will want var y which you can insert into a for loop, and +1 if you don't want 0...19). While it is not shorter if you need to define a function, it is shorter than i?r(i-1).concat(i):[] if you do not need to make a function.

---

Added some performance profiling testcases: it seems that everything besides a standard in-order for-loop is 10x slower, at least on V8. https://jsperf.com/array-range-in-javascript (Of course, none of this matters if you're programming in a functional style anyway and would hit every element with a function call anyway.)

Answer 2

It can be done with features from the ES6, currently only supported by Firefox thou. I found a compatibility table here: http://kangax.github.io/compat-table/es6/

Array.from(new Array(20), (x,i) => i+1)

If you want to have some other range then I guess you could do

Array.from(new Array(5), (x,i) => i+5)

Which would then be [5,6,7,8,9]

Answer 3

You can do this with a while loop where the push happens inside the condition.Array.push returns the length of the array, which happens to be the same as the value in this case. So, you can do the following:

x = []; //normally would use var here
i = 1;  //normally would use var here
while(x.push(i++)<20){}

//at this point, x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]

Condensed version (31 characters)

x=[];i=1;while(x.push(i++)<20);

jsFiddle example

Answer 4

while-- is the way to go

var a=[],b=10;while(b--)a[b]=b+1

returns [1,2,3,4,5,6,7,8,9,10]

explained with start & length

var array=[],length=20,start=5;while(length--)array[length]=length+start

returns [5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24]

want range?

explained with start & end

var array=[],end=30,start=25,a=end-start+1;while(a--)array[a]=end--

returns [25, 26, 27, 28, 29, 30]

for --

for(var a=[],b=20;b>0;b--,a[b]=b+1)

for++

for(var a=[],b=0;b<20;b++,a[b]=b+1)

WHY is this theway to go?

1. while -- is prolly the fastest loop;

2. direct setting is faster than push & concat;

3. [] is also faster than new Array(10);

4. it's not much longer code than all the others

byte saving techniques:

1. use the arguments as a placholder forthe in function variables
2. don't use new Array(),push(),concat() if not needed
3. place "(){};," only when needed.
4. use a,b,c,d... in short functions.

so if u want a function for this

with start,end (range)

function range(a,b,c,d){d=[];c=b-a+1;while(c--)d[c]=b--;return d}

so now range(3,7) returns [3,4,5,6,7]

u save bytes in many ways here and this function is also very fast as it does not use concat, push, new Array and it's made with a while --

Answer 5

If you're OK with 0-20, here are my latest favs from recent code golfing:

[...'0'.repeat(21)].map((_,i)=>i)
Array.from({length:21},(_,i)=>i)
Array(21).fill().map((_,i)=>i)
[...Array(21)].map((_,i)=>i)
Array(21).map((_,i)=>i)
[...Array(21).keys()]

Answer 6

Using ES6

numArr = Array(5).fill(0).reduce(arr=>{ arr.push(arr.length); return arr },[])

Answer 7

if you accept to have a counter starting from 0 instead of 1...

const zeroNineteen = [...Array(20).keys()]; 
// outputs [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19]

if you really need it to start with 1:

const terserst = [...Array(21).keys()].slice(1);

it's 30 characters and yet readable, don't you think?

Answer 8

I can't think of a way with less characters than ~46:

var a=[];while(a.length<20)a.push(a.length+1);

Granted, you could make a function out of that.

Reading your comments about a function, you could do something like

var range = function (start, end) {
    var arr = [];

    while (start <= end) {
        arr.push(start++)
    }

    return arr;
};

Then range(1, 20) would return the array as expected.

Answer 9

If you are looking to shave characters off anyway possible without regard for readability, this is the best I can do:

var x=[],i=0
while(i<20)
  x[i]=i+++1

Not a lot better than yours though.

Edit:

Actually this works better and shaves off a couple characters:

var x=[],i=0
while(i<20)
  x[i]=++i

Edit 2:

And here's my entry for a general "range" function in the least number of characters:

function range(s,e){var x=[];while(s<e+1)x.push(s++);return x}

Again, don't write code this way. :)

Answer 10

I suppose this is the shortest way:

var i=0, arr = [];
while (i++<20){
  arr.push(i);
}

or associating on the 'perverse' code in EndangeredMassa's answer:

var i,arr; while (i=i||1, (arr=arr||[]).push(i++)<20){}

Answer 11

You could always create a function...

function createNumArray(a, b) {
   var arr = [], 
       i = a;

    while((arr[arr.length] = i) < b) {i++}
    return arr;
}

Which allows you to write succinct code later on such as...

var arr = createNumArray(1, 20);

Answer 12

Array.from({length: n}).map((_, i) => i);

Answer 13

In my knowledge, the option of using for loop, as you mentioned, is the most tersest.

That is,

var x = [];
for (var i=1;i<=20;i++) {
  x.push(i);
}

Answer 14

var i = 0;
var x = [];
while (i++ < 20) x.push(i);

JSFiddle

Answer 15

I'd extend Array's prototype to make it simple to access:

Array.prototype.range = function(start, end) {
    if (!this.length) {
        while (end >= start) {
            this.push(start++);
        }
    } else {
        throw "You can only call 'range' on an empty array";
    }
    return this;
};

var array = [].range(1, 20);

---

While the above is the nearest I can think of with respect to the syntactic sugar you're looking for, you may want to try out CoffeeScript.

It supports the notation you're after.

CoffeeScript:

test = [1..20]

alert test

Renders to JavaScript:

var test;
test = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20];
alert(test);

You can try out live examples on their site, and see the conversion it does as you type.

Just click the TRY COFFEESCRIPT link at the top, and you'll get a console where you can test some code.

Answer 16

There's always the IterableInt:

   for (const z of new IterableInt(15)) {
          // 15,14,13....3,2,1
    }

implemented like so:

class IterableInt {


  constructor(val) {
    if (val < 0) {
      throw new Error('cannot iterate over a negative number.')
    }
    this.val = val;
  }

  static create(val){
    return new IterableInt(val);
  }

  [Symbol.iterator]() {

    const self = this;
    return {
      next() {
        const value = self.val--;
        const done = value <= 0;
        return {value, done}
      }
    }
  }
}

to do things like:

  for (const z of new IterableInt(3,15)) {
          // 3,4,5...14,15
    }

go to this gist: https://gist.github.com/ORESoftware/1aca4ae704b355c45702d11c0e245776