Parsing a math formula

Asked Jul 22 '20 at 15:32

Active Jul 22 '20 at 15:32

Viewed 19 times

Why these two codes return different values?

// #1
// a = 11, b = 24, output = 17.5
printf("Avg: %.1f\n", (float)(a + b) / 2);

// #2
// a = 11, b = 24, output = 17.0
printf("Avg: %.1f\n", (float)((a + b) / 2));

I know the problem is in executing, that some thing will be executed first, but that's all I know.

asked Jul 22 '20 at 15:32

John Doe

1

What is types of `a` and `b`? – MikeCAT Jul 22 '20 at 15:33
1

@MikeCAT `short int`. – John Doe Jul 22 '20 at 15:59
`printf("Avg: %.1f\n", ((float)a + b) / 2);}` – 0___________ Jul 22 '20 at 16:28

Parsing a math formula

0 Answers0