How can I delete a specific character from set of tuples?

Question

I want to delete points(".") at the end of every word.

My code looks like this:

a = [('hello.',0) , ('foji.',0),('you',0)]
print([s.strip('.') for s in a])

The output should look something like: [('hello',0) , ('foji',0), ('you',0)]

I get an error says tuple object has no attribute strip! even if i use lists instead i get the same error !

note : using replace doesn't work too.

What should I do to fix this?

Does this answer your question? [Remove specific characters from a string in Python](https://stackoverflow.com/questions/3939361/remove-specific-characters-from-a-string-in-python) — Nicolas Gervais, Jul 22 '20 at 16:26
Think it through. When you iterate with `for s in a`, what do the `s` values look like? What kind of thing are they? Can you `.strip()` that? What is the thing you actually want to call `.strip()` on? Given the `s` value, how do you access that thing? Now, can you figure out the rule to create the desired elements? — Karl Knechtel, Jul 22 '20 at 16:32
To close voters: this is not a duplicate. The problem is not with the logic for manipulating the string; the problem is **accessing** the string. — Karl Knechtel, Jul 22 '20 at 16:33
It's not a duplicate *of what was marked*. And the issue is that OP needs to combine a few concepts - indexing the tuple, applying the transformation to the appropriate part of the tuple, creating the new tuple from there, and wrapping it all up in a comprehension - as in the accepted answer. It's maybe not the best "reference" question for future search-engine users, but it's certainly a reasonably original question. — Karl Knechtel, Jul 22 '20 at 21:24

score 3 · Accepted Answer · answered Jul 22 '20 at 16:26

3

  a = [('hello.',0) , ('foji.',0),('you',0)]
  print([(s[0].replace('.', ''), s[1]) for s in a])

Output:

  [('hello', 0), ('foji', 0), ('you', 0)]

answered Jul 22 '20 at 16:26

badhusha muhammed

score 3 · Answer 2 · answered Jul 22 '20 at 16:28

3

You are working with tuples inside the list so every element is (element1,element2) change your print to

print([(s[0].strip('.'),s[1]) for s in a])

answered Jul 22 '20 at 16:28

Julio González

2 Answers2